| Lecture
        #33 | 
    
        |  | 
            
                | CURMUDGEON
                GENERAL'S WARNING. These "slides"
                represent highlights from lecture and are neither
                complete nor meant to replace lecture. It is
                advised not to use
                these as a reliable means to replace missed
                lecture material. Do so at risk to healthy
                academic performance in 09-105. |  | 
    
        | Lecture Outline | Transition Metal Complexes 
            Crystal Field theory 
                Tetrahedral geometry Hybrid orbitals and bonding | 
    
        | Leaving the discussion of coordination number = 6
        (octahedral geometries) and proceeding to coordination
        number four. |  | 
    
        | Now it becomes clear that the square planar geometry
        correlates with the observation of extra stability of a
        transition metal comlex ion with a d8
        configuration on the central atom |  | 
    
        | Returning to an octahedral geometry, we look at the
        effect of having a weak ligand plus five stronger
        ligands. The weak ligand is assumed to be on the z-axis
        which changes the stability of the transition metal ion
        valence orbitals directed that way |  | 
    
        | Co3+ transition metal complex ions with
        one of the ligands varying shifts the wavelength of light
        absorbed to longer wavelengths as that one ligand becomes
        "weaker" in the field it produces. Transition
        moves "easiest-to-move electron" up to next
        available empty orbital. |  | 
    
        | Measured optical properties (colors) of Co3+
        transition metal complex ions. What do you estimate the
        color of the last complex to be? This last complex is
        meant to be just the trans geometric isomer. |  | 
    
        | The tetrahedral crystal field geometry (without
        demonstrating how to generate the result) turns out to be
        the exact inverse orbital order of that seen in the
        octahedral geometry. |  | 
    
        | Crystal field theory told us nothing about the actual
        bonds. To begin our discussion of bonding in transition
        metal complexes, we return to consideration of hybrid
        atomic orbitals. Here is a review of hybrid atomic
        orbitals for atoms which can have expanded octets as
        would be the case for our transition metal ions. |  | 
    
        | The highest occupied atomic orbital in Cr3+
        and the lowest unoccupied orbitals are shown. The d2sp3
        hybrids can be constructed from appropriate choices here. |  | 
    
        | A review of d2sp3 hybrid atomic
        orbitals |  | 
    
        | The ammonia ligands bind to the transition metal ion.
        In theory, the bond forms in the region of overlap
        between the transition metal ion's hybrid atomic d2sp3
        orbital and the ligand's hybrid sp3 atomic
        orbital. Two electrons go here, both from the ligand, to
        form a sigma bond. |  | 
    
        | Looking in just the xy plane where the sigma bonds to
        four NH3's are located as is the dxy
        non-bonding orbital. The ligand atomic orbital which
        would overlap with the transition metal hybrid orbital (a
        non-bonding interaction) is shown on the x- and y-axes. |  | 
    
        | Fe(H2O)62+ is our
        next example. |  | 
    
        | If we allow iron's six valence electrons to occupy
        the 3d orbital as indicated, each water will contribute a
        lone pair of electrons to a bond between its sp3
        orbital and iron's d2sp3 orbital
        formed as indicated |  | 
    
        | Fe(CO)62+ is our next
        illustration. Since CO is a strong field ligand, we
        should not be surprised to see a low-spin complex ion
        electron configuration show up by necessity. |  | 
    
        | Bonding of the CO ligands to the d2sp3
        hybrid orbitals chosen as illustrated is consistent with
        the complex ion being diamagnetic. |  | 
    
        | Looking in just the xy plane, we see that the
        electron in the dxy nonbonding orbital is
        repelled by chlorine's lone pair in its p-orbital,
        weaking Cl's bond to the metal. |  | 
    
        | Can we now explain why CO (and CN-) are strong field
        ligands? |  | 
    
        | Let's remind ourselves of the underlying valence
        electron structure associated with CO, including the empty
        anti-bonding molecular orbitals. |  | 
    
        | With CO sigma bonded to the metal just as NH3
        and Cl- were, the CO has its empty
        pi-anti-bonding orbital placed so that a delocalized
        molecular orbital in conjunction with the metal's dxy
        becomes possible. Note the constructive interference
        possibility. |  | 
    
        | Here, then is the delocalized orbital into
        which the previously though-to-be-non-bonding electron is
        placed, giving the CO bond to the metal some partial
        pi-bond character...making it a stronger bond! |  | 
    
        | ZnCl42- is the next example. |  | 
    
        | Ten valence electrons fill the zinc 3d orbital. The
        four ligands, each contributing a lone pair to bond
        formation, utilize the hybrids formed from Zn's next four
        orbitals, the 4s and the three 4p's corresponding to sp3
        hybrids and the observed tetrahedral geometry for
        complexes of this type. |  | 
    
        | (This was not included from an earlier lecture.)
        Here's another attempt to show how crystal field
        splitting works, but with coordination number 2, also
        known as linear geometry. |  | 
    
        | This orbital's electron, pointing directly at the
        ligands (with their electrons) is raised in energy. |  | 
    
        | On the other hand, this orbital does not point
        towards the ligands and is unaffected by their presence.
        Likewise for the dxy. |  |