Example Problem:
You are given a 4.0 mg/ml solution of an enzyme (M_{r} = 40,000 Da).
You determine initial velocities (v_{o}) at several concentrations of substrate, [A].

a) Determine K_{m} and V_{max}.

b) Calculate k_{cat} for the reaction.

c) Submit your calculations and a graph of 1/v_{o}vs. 1/[A].

The enzyme concentration = (4 mg/l)/(40,000 g/mol) = 0.10mM (10^{-7} M).
The last two columns were calculated using equations from the Enzyme Kinetics page.

Graph of the calculated results:

The K_{m} = 2.0 mM; V_{max} = 0.5 mM/min.
The k_{cat} = V_{max}/[enzyme] = (0.5 mM/min)/(0.10mM) = 5¥10^{3} min^{-1}.

MM.xls is the Excel spreadsheet used to calculate and graph these results; it can be copied to your disk.